CalcRules

Frustum of a Pyramid

$V o l u m e = \frac{1}{3} h (B_{1} + B_{2} + \sqrt{B_{1} \cdot B_{2}})$

h: Height
B₁: Larger base
B₂: Smaller base

$s i d e l e n g t h = \sqrt{h^{2} + (m_{1} - m_{2})}$

m₁ and m₂: Distance from the center of the base to the side

A frustum can have different types of bases, not only square ones.

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